1997B Part II.
a)

b) The energy must be -1.9 eV, based on the energy emitted by the 600 nm photon.
c) 1240 nm - outside of the visible spectrum
200...Something, #7:
a) There are actually two (correct) ways to draw the diagram:

b) 1240 nm, again, outside of the visible spectrum.
7.
a) 9.9 x 10-15 J
b) 3.3 x 10-23 kg*m/s
c) The photon wavelength increases because some of the energy of the incident photon was lost to KE of the electron.
d) 6.0 x 10-23 kg*m/s
1993B6
a)1.69 x 1019 Hz
b)3.73 x 10-23 kg*m/s
c)3.31 x 10-16 J
d)2.46 x 10-23 kg*m/s
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