Remember everyone - energy is ONLY conserved if the only work is done by conservative forces. Check this EVERY time you use energy conservation to solve a problem.
Solutions:
36. vf = 49.5 m/s
37. vf = (2*g*H)^1/2 = 5.14 m/s
38. (1/2)m^vo^2 + 0 = (1/2)m^vf^2 + mgH
vo = (vf^2 + 2gH)^(1/2) = 6.45 m/s
40. In each case, you must derive that vf = (2*g*(H - h2))^1/2
At B: vf = (2*g*(30 m - 0 m))^1/2 = 24.2 m/s
At C: vf = (2*g*(30 m - ? m))^1/2 = ANSWER PENDING
At D: vf = (2*g*(30 m - 12 m))^1/2 = 18.8 m/s
41.
(1/2)m^vo^2 + mgH = (1/2)m^vf^2 + 0
vf = (2gH + v0^2)^(1/2) = 198.5 m/s.
You do NOT need to use the 45 degrees because vo is the SPEED of the object at the top!
Wednesday, October 29, 2008
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment