Answers from the problems on the back of the handout:
1. delta_x = 300 m
2. final velocity = 8 m/s
3. initial speed = 6.61 m/s
4. t = 0.1714 s
5. time to meet = .636 hrs, position is .184 miles west of flagpole.
HW solutions:
16. acceleration = - 6.25 m/s2 (in opposite direction to initial velocity.) This is the same as .638 g's.
21. delta_x = 150 m
23. delta_x = 62.5 m
25. displacement = -156.25 m, time = 25 s
28.
29. time = 23.96 seconds, speed = 66.61 m/s
Sunday, September 7, 2008
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment